Cell Phone Tested
Cell Phone Tested
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Cell Phone drop test and fracture resistance?
I am wondering how a cell phone drop test is performed and how a force can be calculated on a certain point of a phone or an object when it impacts the ground. If I could calculate that force, I think I could probably design the apparatus or the exterior of a cell phone or any other object to be dropped for that pinpoint location? I am an undergrad college student in engineering. Any help is appreciated.
I know I could just drop it face down to test if the screen would break or not, assuming it hits the screen in the perfect place for maximum damage, but what If I wanted to test it hitting on a certain corner or edge of the phone or object? Since the phone is probably heavier at one end than the other and the center of gravity is probably not in the dead center of the phone, wouldn't the phone have a moment to it and want to turn?
For your purpose, you can consider the phone as a rigid body, thus calculating both deceleration and moment as functions of the distance between the point of interests (e.g. the resistor) and the points of initial and final contact. This would give different forces along the resistor simply by location, as well as the different mass concentrations. A tough problem, in general, probably the ME department would not only take time to solve it, but would still be arguing about whether they got it right.